integral from-1 to 2 of tsin(t^2)+2t^3

Lösung

\int_{- 1}^{2} t sin (t^{2}) + 2 t^{3} d t

\frac{1}{2} (- cos (4) + cos (1)) + \frac{15}{2}

Dezimale

8.09697 \dots

Schritte zur Lösung

\int_{- 1}^{2} t sin (t^{2}) + 2 t^{3} d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} t sin (t^{2}) d t + \int_{- 1}^{2} 2 t^{3} d t

\int_{- 1}^{2} t sin (t^{2}) d t = \frac{1}{2} (- cos (4) + cos (1))

\int_{- 1}^{2} 2 t^{3} d t = \frac{15}{2}

= \frac{1}{2} (- cos (4) + cos (1)) + \frac{15}{2}

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