integral from-1 to 0 of (1-x)

解

\int_{- 1}^{0} (1 - x) d x

\frac{3}{2}

十進法表記

1.5

解答ステップ

\int_{- 1}^{0} 1 - x d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{0} 1 d x - \int_{- 1}^{0} x d x

\int_{- 1}^{0} 1 d x = 1

\int_{- 1}^{0} x d x = - \frac{1}{2}

= 1 - (- \frac{1}{2})

簡素化

1 - (- \frac{1}{2}) : \frac{3}{2}

= \frac{3}{2}