integral from 2 to 3 of (8x^3+3x^2+6x)

Lösung

\int_{2}^{3} (8 x^{3} + 3 x^{2} + 6 x) d x

164

Schritte zur Lösung

\int_{2}^{3} 8 x^{3} + 3 x^{2} + 6 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{3} 8 x^{3} d x + \int_{2}^{3} 3 x^{2} d x + \int_{2}^{3} 6 x d x

\int_{2}^{3} 8 x^{3} d x = 130

\int_{2}^{3} 3 x^{2} d x = 19

\int_{2}^{3} 6 x d x = 15

= 130 + 19 + 15

Vereinfache

= 164

\int_{x^{4}}^{x^{6}} (2 t - 1)^{3} d t

\int_{- 1}^{2} 2 x^{2} - 2 x^{3} + 4 x d x

\int_{- \infty}^{3} e^{- x} d x

\int_{- 5}^{6} (∣ x ∣) d x

\int_{1}^{2} (x^{2} + y^{2}) d y