integral from 0 to pi/2 of-cos(x)+1

Lösung

\int_{0}^{\frac{π}{2}} - cos (x) + 1 d x

- 1 + \frac{π}{2}

Dezimale

0.57079 \dots

Schritte zur Lösung

\int_{0}^{\frac{π}{2}} - cos (x) + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{\frac{π}{2}} cos (x) d x + \int_{0}^{\frac{π}{2}} 1 d x

\int_{0}^{\frac{π}{2}} cos (x) d x = 1

\int_{0}^{\frac{π}{2}} 1 d x = \frac{π}{2}

= - 1 + \frac{π}{2}

\int_{0}^{e} 1

\int_{0}^{3} (5 t - 9) d t

\int_{6}^{14} x^{2} d x

\int_{0}^{t} sin (a) d a

\int_{\frac{π}{4}}^{\frac{π}{2}} (- 2 cot (x) csc^{2} (x)) d x