integral from 0 to 2pi of 1/6

Lösung

\int_{0}^{2 π} \frac{1}{6} d θ

\frac{π}{3}

Dezimale

1.04719 \dots

Schritte zur Lösung

\int_{0}^{2 π} \frac{1}{6} d θ

Integral einer Konstanten :

\int a d x = a x

= [\frac{1}{6} θ]_{0}^{2 π}

Berechne die Grenzen:

\frac{π}{3}

= \frac{π}{3}

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