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人気のある微分積分 >

integral from-2 to-u^2 of 1/2

解

\int_{- 2}^{- u^{2}} \frac{1}{2} d v

解

- \frac{u ^{2}}{2} + 1

解答ステップ

\int_{- 2}^{- u^{2}} \frac{1}{2} d v

定数の積分:

\int a d x = a x

= [\frac{1}{2} v]_{- 2}^{- u^{2}}

限度を計算する:

- \frac{1}{2} u^{2} + 1

= - \frac{1}{2} u^{2} + 1

簡素化

= - \frac{u ^{2}}{2} + 1

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