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人気のある微分積分 >

integral from 1 to 0 of (2x+3)

解

\int_{1}^{0} (2 x + 3) d x

解

- 4

解答ステップ

\int_{1}^{0} 2 x + 3 d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{1} 2 x + 3 d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - (\int_{0}^{1} 2 x d x + \int_{0}^{1} 3 d x)

\int_{0}^{1} 2 x d x = 1

\int_{0}^{1} 3 d x = 3

= - (1 + 3)

簡素化

= - 4

グラフ

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