What is the integral of integral of integral of z ?

The integral of integral of integral of z is Cz+y(Cz+(xz^2)/2)+C

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integral of integral of integral of z

\int \int \int z d x d y d z

C z + y (C z + \frac{x z ^{2}}{2}) + C

Solution steps

\int \int \int z d x d y d z

\int z d x = z x + C

= \int \int (z x + C) d y d z

\int (z x + C) d y = (C + z x) y + C

= \int ((C + z x) y + C) d z

\int ((C + z x) y + C) d z = C z + y (C z + \frac{x z ^{2}}{2}) + C

= C z + y (C z + \frac{x z ^{2}}{2}) + C

What is the integral of integral of integral of z ?
The integral of integral of integral of z is Cz+y(Cz+(xz^2)/2)+C