What is the limit as x approaches 4 of x^2-4x+3 ?

The limit as x approaches 4 of x^2-4x+3 is 3

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limit as x approaches 4 of x^2-4x+3

x \to 4 lim (x^{2} - 4 x + 3)

3

Solution steps

x \to 4 lim (x^{2} - 4 x + 3)

Plug in the value

x = 4

= 4^{2} - 4 \cdot 4 + 3

Simplify

= 3

x \to π lim (15 - sin (x))

x \to 0 lim (2 ln (x))

x \to \infty lim (\frac{2 x - 3}{3 x - 2})

x \to 1 + lim (x - 3)

x \to 0 lim (\frac{3 ^{x} - 7 ^{x}}{x})

What is the limit as x approaches 4 of x^2-4x+3 ?
The limit as x approaches 4 of x^2-4x+3 is 3