limit as x approaches 1 of (6x+1)/(x-1)

Lösung

x \to 1 lim (\frac{6 x + 1}{x - 1})

divergiert

Schritte zur Lösung

x \to 1 lim (\frac{6 x + 1}{x - 1})

Wenn

x \to a - lim f (x) \neq = x \to a + lim f (x)

dann gibt es keine Grenze

x \to 1 + lim (\frac{6 x + 1}{x - 1}) = \infty

x \to 1 - lim (\frac{6 x + 1}{x - 1}) = - \infty

= divergiert

x \to 0 lim (\frac{tan ( x )}{x} cos (x))

x \to \infty lim ((\frac{1 + 9}{x})^{(\frac{x}{8})})

x \to \infty lim (- \infty + ln (2))

x \to 0 lim (\frac{x + π sec ( x )}{x ^{2} - π ^{2}})

x \to 0 lim (3 x)