derivative g(x)=3^{2x+7}

解

導関数

g (x) = 3^{2 x + 7}

2 ln (3) \cdot 3^{2 x + 7}

解答ステップ

\frac{d}{d x} (3^{2 x + 7})

指数の規則を適用する:

a^{b} = e^{b l n (a)}

3^{2 x + 7} = e^{(2 x + 7) l n (3)}

= \frac{d}{d x} (e^{(2 x + 7) l n (3)})

連鎖法則を適用:

e^{(2 x + 7) l n (3)} \frac{d}{d x} ((2 x + 7) ln (3))

= e^{(2 x + 7) l n (3)} \frac{d}{d x} ((2 x + 7) ln (3))

\frac{d}{d x} ((2 x + 7) ln (3)) = 2 ln (3)

= e^{(2 x + 7) l n (3)} \cdot 2 ln (3)

e^{(2 x + 7) l n (3)} = 3^{2 x + 7}

= 2 ln (3) \cdot 3^{2 x + 7}