integral cos^7(x)

Lösung

integral

cos^{7} (x)

sin (x) - sin^{3} (x) + \frac{3 sin ^{5} ( x )}{5} - \frac{sin ^{7} ( x )}{7} + C

Schritte zur Lösung

\int cos^{7} (x) d x

Umschreiben mit Hilfe von Trigonometrie-Identitäten

= \int (1 - sin^{2} (x))^{3} cos (x) d x

Wende U-Substitution an

= \int (1 - u^{2})^{3} d u

Multipliziere aus

(1 - u^{2})^{3} : 1 - 3 u^{2} + 3 u^{4} - u^{6}

= \int 1 - 3 u^{2} + 3 u^{4} - u^{6} d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d u - \int 3 u^{2} d u + \int 3 u^{4} d u - \int u^{6} d u

\int 1 d u = u

\int 3 u^{2} d u = u^{3}

\int 3 u^{4} d u = \frac{3 u ^{5}}{5}

\int u^{6} d u = \frac{u ^{7}}{7}

= u - u^{3} + \frac{3 u ^{5}}{5} - \frac{u ^{7}}{7}

Setze in

u = sin (x)

ein

= sin (x) - sin^{3} (x) + \frac{3 sin ^{5} ( x )}{5} - \frac{sin ^{7} ( x )}{7}

Füge eine Konstante zur Lösung hinzu

= sin (x) - sin^{3} (x) + \frac{3 sin ^{5} ( x )}{5} - \frac{sin ^{7} ( x )}{7} + C

in t e g r a l \frac{1}{( 1 + x ^{4} )}

in t e g r a l \frac{x ^{3}}{( x + 2 )}

in t e g r a l \frac{1}{( a ^{2} - x ^{2} )}

in t e g r a l \frac{x ^{2}}{( 1 - x )}

in t e g r a l \frac{k \cdot x}{( 1 + x ^{2} )}