(d^3+4d)y=4cot(2x)

Lösung

(d^{3} + 4 d) y = 4 cot (2 x)

y = c_{1} + c_{2} cos (2 x) + c_{3} sin (2 x) + \frac{ln ( sin ( 2 x ) ) + cos ( 2 x ) ( - ln ( tan ( x ) ) - cos ( 2 x ) ) - sin ^{2} ( 2 x )}{2}

Schritte zur Lösung

(d^{3} + 4 d) y = 4 cot (2 x)

Solve linear ODE:

y = c_{1} + c_{2} cos (2 x) + c_{3} sin (2 x) + \frac{ln ( sin ( 2 x ) ) + cos ( 2 x ) ( - ln ( tan ( x ) ) - cos ( 2 x ) ) - sin ^{2} ( 2 x )}{2}

y = c_{1} + c_{2} cos (2 x) + c_{3} sin (2 x) + \frac{ln ( sin ( 2 x ) ) + cos ( 2 x ) ( - ln ( tan ( x ) ) - cos ( 2 x ) ) - sin ^{2} ( 2 x )}{2}

d (x) = 243 e^{- 0} 0.1 x

(d^{2} - 2 d) y = e^{x} + e^{- x}

(d^{2} - 7 d + 10) y = 5 x + 7

y^{^{''}} + 4 y = 5 e^{x}

(d^{2} - 8 d + 9) y = 8 sin^{5} (x)