(d^3-d)*y=x

Lösung

(d^{3} - d) \cdot y = x

y = c_{1} + c_{2} e^{- x} + c_{3} e^{x} - \frac{x ^{2}}{2}

Schritte zur Lösung

(d^{3} - d) y = x

Solve linear ODE:

y = c_{1} + c_{2} e^{- x} + c_{3} e^{x} - \frac{x ^{2}}{2}

y = c_{1} + c_{2} e^{- x} + c_{3} e^{x} - \frac{x ^{2}}{2}

(d^{2} + 2 d + 3) y = sin (x)

y^{^{'''}} - 3 y^{^{''}} + 4 y^{^{'}} - 2 y = e^{x}

(d^{2} - 1) y = x sin^{3} (x) + cos (x)

(d^{4} + 8 d^{2} + 16) \cdot y = - 2

(d^{2} + 3 d + 2) y = e^{2} x + sin (x)