y^'=-12y-6,y(0)=1

Lösung

y^{^{'}} = - 12 y - 6, y (0) = 1

y = \frac{3 e ^{- 12 t}}{2} - \frac{1}{2}

Schritte zur Lösung

y^{'} (t) = - 12 y - 6

Solve separable ODE:

y = \frac{3 e ^{- 12 t}}{2} - \frac{1}{2}

y = \frac{3 e ^{- 12 t}}{2} - \frac{1}{2}

y^{^{'}} + (x + 1) y^{3} = 0

y^{^{'}} + x y^{5} = 0

y^{^{'}} = \frac{- y}{3 x}

(x y - y) y^{^{'}} = x^{2} y - y + x^{2} - 1

y^{^{'}} + y^{5} = 0