integral of (4x^2+1)^{3/2}

Lösung

\int (4 x^{2} + 1)^{\frac{3}{2}} d x

\frac{1}{4} x (4 x^{2} + 1)^{\frac{3}{2}} + \frac{3}{8} x 4 x^{2} + 1 + \frac{3}{16} ln 2 x + 4 x^{2} + 1 + C

Schritte zur Lösung

\int (4 x^{2} + 1)^{\frac{3}{2}} d x

Wende die partielle Integration an

= x (4 x^{2} + 1)^{\frac{3}{2}} - \int 12 x^{2} (4 x^{2} + 1)^{\frac{1}{2}} d x

\int 12 x^{2} (4 x^{2} + 1)^{\frac{1}{2}} d x = \frac{3}{16} (4 x (4 x^{2} + 1)^{\frac{3}{2}} - 2 x 4 x^{2} + 1 - ln 2 x + 4 x^{2} + 1)

= x (4 x^{2} + 1)^{\frac{3}{2}} - \frac{3}{16} (4 x (4 x^{2} + 1)^{\frac{3}{2}} - 2 x 4 x^{2} + 1 - ln 2 x + 4 x^{2} + 1)

Vereinfache

x (4 x^{2} + 1)^{\frac{3}{2}} - \frac{3}{16} (4 x (4 x^{2} + 1)^{\frac{3}{2}} - 2 x 4 x^{2} + 1 - ln 2 x + 4 x^{2} + 1) : \frac{1}{4} x (4 x^{2} + 1)^{\frac{3}{2}} + \frac{3}{8} x 4 x^{2} + 1 + \frac{3}{16} ln 2 x + 4 x^{2} + 1

= \frac{1}{4} x (4 x^{2} + 1)^{\frac{3}{2}} + \frac{3}{8} x 4 x^{2} + 1 + \frac{3}{16} ln 2 x + 4 x^{2} + 1

Füge eine Konstante zur Lösung hinzu

= \frac{1}{4} x (4 x^{2} + 1)^{\frac{3}{2}} + \frac{3}{8} x 4 x^{2} + 1 + \frac{3}{16} ln 2 x + 4 x^{2} + 1 + C

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