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integral of (6x^3+5x)^{12}

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解答

∫(6x3+5x)12dx

解答

37612x37​+74353564672x35​+3023308800x33+31277136640000x31​+29519631200000x29​+25660800000x27+26943840000x25+23481140000000x23​+783531250000x21​+1992812500000x19​+1723203125000x17​+234375000x15+13244140625x13​+C
求解步骤
∫(6x3+5x)12dx
乘开 (6x3+5x)12:612x36+21767823360x34+99769190400x32+277136640000x30+519631200000x28+692841600000x26+673596000000x24+481140000000x22+250593750000x20+92812500000x18+23203125000x16+3515625000x14+244140625x12
=∫612x36+21767823360x34+99769190400x32+277136640000x30+519631200000x28+692841600000x26+673596000000x24+481140000000x22+250593750000x20+92812500000x18+23203125000x16+3515625000x14+244140625x12dx
使用积分加法定则: ∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx=∫612x36dx+∫21767823360x34dx+∫99769190400x32dx+∫277136640000x30dx+∫519631200000x28dx+∫692841600000x26dx+∫673596000000x24dx+∫481140000000x22dx+∫250593750000x20dx+∫92812500000x18dx+∫23203125000x16dx+∫3515625000x14dx+∫244140625x12dx
∫612x36dx=37612x37​
∫21767823360x34dx=74353564672x35​
∫99769190400x32dx=3023308800x33
∫277136640000x30dx=31277136640000x31​
∫519631200000x28dx=29519631200000x29​
∫692841600000x26dx=25660800000x27
∫673596000000x24dx=26943840000x25
∫481140000000x22dx=23481140000000x23​
∫250593750000x20dx=783531250000x21​
∫92812500000x18dx=1992812500000x19​
∫23203125000x16dx=1723203125000x17​
∫3515625000x14dx=234375000x15
∫244140625x12dx=13244140625x13​
=37612x37​+74353564672x35​+3023308800x33+31277136640000x31​+29519631200000x29​+25660800000x27+26943840000x25+23481140000000x23​+783531250000x21​+1992812500000x19​+1723203125000x17​+234375000x15+13244140625x13​
解答补常数=37612x37​+74353564672x35​+3023308800x33+31277136640000x31​+29519631200000x29​+25660800000x27+26943840000x25+23481140000000x23​+783531250000x21​+1992812500000x19​+1723203125000x17​+234375000x15+13244140625x13​+C

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