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Popular Calculus >

integral of (2e^2)^x

Solution

\int (2 e^{2})^{x} d x

Solution

\frac{1}{ln ( 2 ) + 2} (2 e^{2})^{x} + C

Solution steps

\int (2 e^{2})^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= \frac{( 2 e ^{2} ) ^{x}}{ln ( 2 e ^{2} )}

Simplify

\frac{( 2 e ^{2} ) ^{x}}{ln ( 2 e ^{2} )} : \frac{1}{ln ( 2 ) + 2} (2 e^{2})^{x}

= \frac{1}{ln ( 2 ) + 2} (2 e^{2})^{x}

Add a constant to the solution

= \frac{1}{ln ( 2 ) + 2} (2 e^{2})^{x} + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of (2e^2)^x ?
The integral of (2e^2)^x is 1/(ln(2)+2)(2e^2)^x+C