integral of (cosh(4x)+sinh(2x))

Lösung

\int (cosh (4 x) + sinh (2 x)) d x

\frac{1}{4} sinh (4 x) + \frac{1}{2} cosh (2 x) + C

Schritte zur Lösung

\int cosh (4 x) + sinh (2 x) d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int cosh (4 x) d x + \int sinh (2 x) d x

\int cosh (4 x) d x = \frac{1}{4} sinh (4 x)

\int sinh (2 x) d x = \frac{1}{2} cosh (2 x)

= \frac{1}{4} sinh (4 x) + \frac{1}{2} cosh (2 x)

Füge eine Konstante zur Lösung hinzu

= \frac{1}{4} sinh (4 x) + \frac{1}{2} cosh (2 x) + C

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