What is the integral of (x+10)/(x^2+3x+2) ?

The integral of (x+10)/(x^2+3x+2) is 9ln|x+1|-8ln|x+2|+C

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integral of (x+10)/(x^2+3x+2)

\int \frac{x + 10}{x ^{2} + 3 x + 2} d x

9 ln ∣ x + 1 ∣ - 8 ln ∣ x + 2 ∣ + C

Solution steps

\int \frac{x + 10}{x ^{2} + 3 x + 2} d x

Take the partial fraction of

\frac{x + 10}{x ^{2} + 3 x + 2} : \frac{9}{x + 1} - \frac{8}{x + 2}

= \int \frac{9}{x + 1} - \frac{8}{x + 2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{9}{x + 1} d x - \int \frac{8}{x + 2} d x

\int \frac{9}{x + 1} d x = 9 ln ∣ x + 1 ∣

\int \frac{8}{x + 2} d x = 8 ln ∣ x + 2 ∣

= 9 ln ∣ x + 1 ∣ - 8 ln ∣ x + 2 ∣

Add a constant to the solution

= 9 ln ∣ x + 1 ∣ - 8 ln ∣ x + 2 ∣ + C

What is the integral of (x+10)/(x^2+3x+2) ?
The integral of (x+10)/(x^2+3x+2) is 9ln|x+1|-8ln|x+2|+C