integral of 1/(s^2+1)

解答

\int \frac{1}{s ^{2} + 1} d s

arctan (s) + C

求解步骤

\int \frac{1}{s ^{2} + 1} d s

使用积分常见定则:

\int \frac{1}{s ^{2} + 1} d s = arctan (s)

= arctan (s)

解答补常数

= arctan (s) + C

\frac{\partial}{\partial x} (e^{9 x + 5 y})

\frac{d}{d x} (\frac{2 x ^{2} + 1}{( 1 - x ^{2} ) ^{\frac{5}{2}}})

\int \frac{1}{2 \cdot tan ( x )} d x

\int \frac{x}{x + 3 x} d x

\frac{d}{d x} ((\frac{1}{x ^{2}} - \frac{9}{x ^{4}}) (x + 5 x^{3}))