integral from 1 to 2 of (3x-4)(x-1)

Lösung

\int_{1}^{2} (3 x - 4) (x - 1) d x

\frac{1}{2}

Dezimale

0.5

Schritte zur Lösung

\int_{1}^{2} (3 x - 4) (x - 1) d x

Wende die partielle Integration an

= [(3 x - 4) (\frac{x ^{2}}{2} - x) - \int 3 (\frac{x ^{2}}{2} - x) d x]_{1}^{2}

\int 3 (\frac{x ^{2}}{2} - x) d x = 3 (\frac{x ^{3}}{6} - \frac{x ^{2}}{2})

= [(3 x - 4) (\frac{x ^{2}}{2} - x) - 3 (\frac{x ^{3}}{6} - \frac{x ^{2}}{2})]_{1}^{2}

Berechne die Grenzen:

\frac{1}{2}

= \frac{1}{2}

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