What is the integral of 4/(\sqrt[3]{x)} ?

The integral of 4/(\sqrt[3]{x)} is 6x^{2/3}+C

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integral of 4/(\sqrt[3]{x)}

6 x^{\frac{2}{3}} + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

= 4 \cdot \frac{3}{2} x^{\frac{2}{3}}

Simplify

4 \cdot \frac{3}{2} x^{\frac{2}{3}} : 6 x^{\frac{2}{3}}

= 6 x^{\frac{2}{3}}

Add a constant to the solution

= 6 x^{\frac{2}{3}} + C

What is the integral of 4/(\sqrt[3]{x)} ?
The integral of 4/(\sqrt[3]{x)} is 6x^{2/3}+C