What is the tangent of y= 1/(1+x^2),(-1, 1/2) ?

The tangent of y= 1/(1+x^2),(-1, 1/2) is y= 1/2 x+1

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tangent of y= 1/(1+x^2),(-1, 1/2)

tangent of

y = \frac{1}{1 + x ^{2}}, (- 1, \frac{1}{2})

y = \frac{1}{2} x + 1

Solution steps

Find the slope of

y = \frac{1}{1 + x ^{2}} : \frac{d y}{d x} = - \frac{2 x}{( 1 + x ^{2} ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(- 1, \frac{1}{2}) : y = \frac{1}{2} x + 1

y = \frac{1}{2} x + 1

What is the tangent of y= 1/(1+x^2),(-1, 1/2) ?
The tangent of y= 1/(1+x^2),(-1, 1/2) is y= 1/2 x+1