integral from 0 to 3 of 1/(sqrt(36-z^2))

Lösung

\int_{0}^{3} \frac{1}{36 - z ^{2}} d z

\frac{π}{6}

Dezimale

0.52359 \dots

Schritte zur Lösung

\int_{0}^{3} \frac{1}{36 - z ^{2}} d z

Trigonometrische Substitution anwenden

= \int_{0}^{\frac{π}{6}} 1 d u

Integral einer Konstanten :

\int a d x = a x

= [1 \cdot u]_{0}^{\frac{π}{6}}

Vereinfache

= [u]_{0}^{\frac{π}{6}}

Berechne die Grenzen:

\frac{π}{6}

= \frac{π}{6}

\int_{1}^{\frac{π}{2}} sin (x) d x

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