integral from 0 to 2pi of 9tsqrt(2)

Lösung

\int_{0}^{2 π} 9 t 2 d t

182 π^{2}

Dezimale

251.23911 \dots

Schritte zur Lösung

\int_{0}^{2 π} 9 t 2 d t

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 92 \cdot \int_{0}^{2 π} t d t

Wende die Potenzregel an

= 92 [\frac{t ^{2}}{2}]_{0}^{2 π}

Berechne die Grenzen:

2 π^{2}

= 92 \cdot 2 π^{2}

Vereinfache

= 182 π^{2}

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