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人気のある微分積分 >

integral from-8 to 3 of sqrt(1+|x|)

解

\int_{- 8}^{3} 1 + ∣ x ∣ d x

解

22

解答ステップ

\int_{- 8}^{3} 1 + ∣ x ∣ d x

絶対数を排除する

= \int_{- 8}^{0} 1 - x d x + \int_{0}^{3} 1 + x d x

\int_{- 8}^{0} 1 - x d x = \frac{52}{3}

\int_{0}^{3} 1 + x d x = \frac{14}{3}

= \frac{52}{3} + \frac{14}{3}

簡素化

\frac{52}{3} + \frac{14}{3} : 22

= 22

グラフ

人気の例

integral from-2 to 1 of (x^2+1)^2

\int_{- 2}^{1} (x^{2} + 1)^{2} d x

integral from a to b of ln(r^2)r

\int_{a}^{b} ln (r^{2}) r d r

integral from 0 to 8 of 2sqrt(x)+3

\int_{0}^{8} 2 x + 3 d x

integral from-2 to 2 of x/(1-x)

\int_{- 2}^{2} \frac{x}{1 - x} d x

integral from 0 to 4 of |x^2-1|

\int_{0}^{4} x^{2} - 1 d x