integral from 0 to 1 of cos(x+y)

Lösung

\int_{0}^{1} cos (x + y) d x

sin (y + 1) - sin (y)

Schritte zur Lösung

\int_{0}^{1} cos (x + y) d x

Wende U-Substitution an

= \int_{y}^{y + 1} cos (u) d u

Nutze das gemeinsame Integral :

\int cos (u) d u = sin (u)

= [sin (u)]_{y}^{y + 1}

Berechne die Grenzen:

sin (y + 1) - sin (y)

= sin (y + 1) - sin (y)

\int_{1}^{3} \frac{x ^{4} + 1}{x ^{2}} d x

\int_{0}^{6} ∣ 3 - x ∣ d x

\int_{3 x^{2} - 6 x}^{2 x - x^{2}} (3 x) d x

\int_{2}^{4} 3 x^{3} d x

\int_{0}^{1} 1 + 4 x d x