integral from 0 to 3 of 2x(x^2+1)^3

Lösung

\int_{0}^{3} 2 x (x^{2} + 1)^{3} d x

\frac{9999}{4}

Dezimale

2499.75

Schritte zur Lösung

\int_{0}^{3} 2 x (x^{2} + 1)^{3} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{3} x (x^{2} + 1)^{3} d x

Multipliziere aus

x (x^{2} + 1)^{3} : x^{7} + 3 x^{5} + 3 x^{3} + x

= 2 \cdot \int_{0}^{3} x^{7} + 3 x^{5} + 3 x^{3} + x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (\int_{0}^{3} x^{7} d x + \int_{0}^{3} 3 x^{5} d x + \int_{0}^{3} 3 x^{3} d x + \int_{0}^{3} x d x)

\int_{0}^{3} x^{7} d x = \frac{6561}{8}

\int_{0}^{3} 3 x^{5} d x = \frac{729}{2}

\int_{0}^{3} 3 x^{3} d x = \frac{243}{4}

\int_{0}^{3} x d x = \frac{9}{2}

= 2 (\frac{6561}{8} + \frac{729}{2} + \frac{243}{4} + \frac{9}{2})

Vereinfache

2 (\frac{6561}{8} + \frac{729}{2} + \frac{243}{4} + \frac{9}{2}) : \frac{9999}{4}

= \frac{9999}{4}

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