integral from 0 to 6pi of θsqrt(θ^2+4)

Lösung

\int_{0}^{6 π} θ θ^{2} + 4 d θ

\frac{( 36 π ^{2} + 4 ) ^{\frac{3}{2}} - 8}{3}

Dezimale

2267.59027 \dots

Schritte zur Lösung

\int_{0}^{6 π} θ θ^{2} + 4 d θ

Wende U-Substitution an

= \int_{2}^{36 π^{2} + 4} u^{2} d u

Wende die Potenzregel an

= [\frac{u ^{3}}{3}]_{2}^{36 π^{2} + 4}

Berechne die Grenzen:

\frac{( 36 π ^{2} + 4 ) ^{\frac{3}{2}}}{3} - \frac{8}{3}

= \frac{( 36 π ^{2} + 4 ) ^{\frac{3}{2}}}{3} - \frac{8}{3}

Vereinfache

= \frac{( 36 π ^{2} + 4 ) ^{\frac{3}{2}} - 8}{3}

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