sum from k=0 to infinity of (-2/3)^k

Lösung

k = 0 \sum \infty (- \frac{2}{3})^{k}

\frac{3}{5}

Dezimale

0.6

Schritte zur Lösung

k = 0 \sum \infty (- \frac{2}{3})^{k}

Geometrischen Test der Reihe anwenden:

\frac{3}{5}

= \frac{3}{5}

n = 0 \sum \infty \frac{3}{5 ^{n + 2}}

n = 1 \sum \infty \frac{e}{π ^{n}}

n = 1 \sum \infty ln (n^{2})

n = 1 \sum \infty n e^{2 n}

n = 1 \sum \infty \frac{( 1 )}{n}