sum from n=1 to infinity of 6/(5^n)

Lösung

n = 1 \sum \infty \frac{6}{5 ^{n}}

\frac{3}{2}

Dezimale

1.5

Schritte zur Lösung

n = 1 \sum \infty \frac{6}{5 ^{n}}

Wende die Regel der konstanten Multiplikation:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 6 \cdot n = 1 \sum \infty \frac{1}{5 ^{n}}

n = k \sum \infty (a_{n}) = n = 0 \sum \infty (a_{n}) - a_{0} - a_{1} - \dots a_{k - 1}

= 6 (n = 0 \sum \infty \frac{1}{5 ^{n}} - \frac{1}{5 ^{0}})

n = 0 \sum \infty \frac{1}{5 ^{n}} = \frac{5}{4}

= 6 (\frac{5}{4} - \frac{1}{5 ^{0}})

Vereinfache

6 (\frac{5}{4} - \frac{1}{5 ^{0}}) : \frac{3}{2}

= \frac{3}{2}