y^'-x/(5y^4)=0

Lösung

y^{^{'}} - \frac{x}{5 y ^{4}} = 0

y = 5 \frac{x ^{2}}{2} + c_{1}

Schritte zur Lösung

y^{'} (x) - \frac{x}{5 y ^{4}} = 0

Solve separable ODE:

y = 5 \frac{x ^{2}}{2} + c_{1}

y = 5 \frac{x ^{2}}{2} + c_{1}

\frac{d y}{d x} = \frac{cos ^{2} ( x )}{y}

\frac{d y}{d x} - x = x y^{2}

5 y^{4} \frac{d y}{d x} = 12 x

x^{^{'}} = \frac{( x ^{2} - 1 )}{2}

\frac{d h}{d t} = - \frac{3}{100} h - 15