y^'=tan(y)tan(x)

Lösung

y^{^{'}} = tan (y) tan (x)

y = arcsin (\frac{c _{1}}{cos ( x )}) + 2 πn, y = π + arcsin (- \frac{c _{1}}{cos ( x )}) + 2 πn

Schritte zur Lösung

y^{'} (x) = tan (y) tan (x)

Solve separable ODE:

y = arcsin (\frac{c _{1}}{cos ( x )}) + 2 πn, y = π + arcsin (- \frac{c _{1}}{cos ( x )}) + 2 πn

y = arcsin (\frac{c _{1}}{cos ( x )}) + 2 πn, y = π + arcsin (- \frac{c _{1}}{cos ( x )}) + 2 πn

y^{^{'}} = y - 2 y^{2}

y^{^{'}} = 6 x y - 3 y

y^{^{'}} = x y^{\frac{3}{2}}

y^{^{'}} = \frac{x}{2 y}

(1 + y^{2}) cos (x) d x - \frac{1}{x} d y = 0, y (0) = \frac{π}{4}