xy^2y^'=x+5

Lösung

x y^{2} y^{^{'}} = x + 5

y = 3 3 x + 15 ln (x) + c_{1}

Schritte zur Lösung

x y^{2} y^{'} (x) = x + 5

Solve separable ODE:

y = 3 3 x + 15 ln (x) + c_{1}

y = 3 3 x + 15 ln (x) + c_{1}

y^{^{'}} = e^{2 x + 3 y}, y (0) = 0

\frac{d P}{d t} = 0.1 P (1 - \frac{P}{40})

y^{^{'}} = - 4 y + 2

\frac{d y}{d x} + 12 x y = - x

x^{2} \frac{d y}{d x} + 8 x \frac{d y}{d x} + 6 y = 0