y^2y^'-cos(x)=0

Lösung

y^{2} y^{^{'}} - cos (x) = 0

y = 3 3 sin (x) + c_{1}

Schritte zur Lösung

y^{2} y^{'} (x) - cos (x) = 0

Solve separable ODE:

y = 3 3 sin (x) + c_{1}

y = 3 3 sin (x) + c_{1}

(1 + y^{2}) cos (x) d x - \frac{1}{x} d y = 0

\frac{d v}{d t} = 4 - 6 v

\frac{d y}{d x} = \frac{2 x + sec ^{2} ( x )}{2 y}, y (0) = - 5

x y^{^{'}} = (1 + y)^{\frac{1}{2}}

x y + x y^{^{'}} = x