(y+x^2ye^{2x})dx-(x+xy)dy=0

Lösung

(y + x^{2} y e^{2 x}) d x - (x + x y) d y = 0

y = W (\frac{x}{e ^{\frac{- 2 e ^{2 x} x + e ^{2 x} - c _{1}}{4}}})

Schritte zur Lösung

(y + x^{2} y e^{2 x}) d x - (x + x y) d y = 0

Solve separable ODE:

y = W (\frac{x}{e ^{\frac{- 2 e ^{2 x} x + e ^{2 x} - c _{1}}{4}}})

y = W (\frac{x}{e ^{\frac{- 2 e ^{2 x} x + e ^{2 x} - c _{1}}{4}}})

y^{^{'}} + y = y^{6}

y^{^{'}} = \frac{11 x ^{2} - 1}{11 + 9 y}

(x^{2} + 1) d x - 3 y d y = 0

e^{x + y} \frac{d x}{d y} = x

\frac{d q}{d t} = k q (t)^{2}