y^'=(1+x)/y

Lösung

y^{^{'}} = \frac{1 + x}{y}

y = 2 x + x^{2} + c_{1}, y = - 2 x + x^{2} + c_{1}

Schritte zur Lösung

y^{'} (x) = \frac{1 + x}{y}

Solve separable ODE:

y = 2 x + x^{2} + c_{1}, y = - 2 x + x^{2} + c_{1}

y = 2 x + x^{2} + c_{1}, y = - 2 x + x^{2} + c_{1}

\frac{d y}{d x} = (9 + y^{2}) (3 + x^{2})

y^{^{'}} = 3 y^{2} - 3 y

x^{3} y^{^{'}} - (8 x^{2} - 5) y = 0, y (1) = 2

\frac{d y}{d x} = cy - 1

\frac{d y}{d x} = \frac{( x + 2 )}{2 y}