(1+2y)xdx+(1+x^2)dy=0

Lösung

(1 + 2 y) x d x + (1 + x^{2}) d y = 0

y = \frac{c _{1}}{2 ( 1 + x ^{2} )} - \frac{1}{2}

Schritte zur Lösung

(1 + 2 y) x d x + (1 + x^{2}) d y = 0

Solve separable ODE:

y = \frac{c _{1}}{2 ( 1 + x ^{2} )} - \frac{1}{2}

y = \frac{c _{1}}{2 ( 1 + x ^{2} )} - \frac{1}{2}

\frac{d y}{d x} = e^{(x + y)}

x y^{^{'}} - y = 1

y y^{^{'}} = x^{2} + x, y (13) = 20

\frac{d y}{d x} = 1 - x + y - x y

y^{^{'}} = x (y - 1)