x^2y^'=xy^2

Lösung

x^{2} y^{^{'}} = x y^{2}

y = - \frac{1}{ln ( x ) + c _{1}}

Schritte zur Lösung

x^{2} y^{'} (x) = x y^{2}

Solve separable ODE:

y = - \frac{1}{ln ( x ) + c _{1}}

y = - \frac{1}{ln ( x ) + c _{1}}

y^{^{'}} = \frac{4 y ^{2}}{x}

cos (2 y) d y = d x

y d x + (x - 1) d y = 0, y (2) = 25

2 y y^{^{'}} = 18 t^{2}, y (0) = 7

\frac{d y}{d t} + 2 y = 5, y (0) = 1