5x^'+7x=15

Lösung

5 x^{^{'}} + 7 x = 15

x = - \frac{e ^{\frac{- 7 t - c _{1}}{5}}}{7} + \frac{15}{7}

Schritte zur Lösung

5 x^{'} (t) + 7 x = 15

Solve separable ODE:

x = - \frac{e ^{\frac{- 7 t - c _{1}}{5}}}{7} + \frac{15}{7}

x = - \frac{e ^{\frac{- 7 t - c _{1}}{5}}}{7} + \frac{15}{7}

\frac{d y}{d x} = y x^{2} - 1.1 y, y (0) = 1

y^{^{'}} + 2 y = - 4

y^{^{'}} = - \frac{5 x ^{4} - 5}{4 y}

y^{^{'}} = y - 2 y^{2}, y (0) = t (t)

\frac{d y}{d x} = - \frac{4}{9} x^{6} y^{4}