y^'=(cos(x))y^2

Lösung

y^{^{'}} = (cos (x)) y^{2}

y = - \frac{1}{sin ( x ) + c _{1}}

Schritte zur Lösung

y^{'} (x) = (cos (x)) y^{2}

Solve separable ODE:

y = - \frac{1}{sin ( x ) + c _{1}}

y = - \frac{1}{sin ( x ) + c _{1}}

\frac{d y}{d x} (x^{2} + 1) + 3 x (y - 1) = 0

x^{4} y^{^{'}} = 3 - 2 y

\frac{d y}{d x} + y^{2} sin (4 x) = 0

e^{- 3 x} \frac{d y}{d x} - 3 e^{- 3 x} y = 0

x^{^{'}} = 5.5 - x