y^'cos(y)+2xsin(y)=-2x

Lösung

y^{^{'}} cos (y) + 2 x sin (y) = - 2 x

y = arcsin (e^{- x^{2} + c_{1}} - 1) + 2 πn, y = π + arcsin (- e^{- x^{2} + c_{1}} + 1) + 2 πn

Schritte zur Lösung

y^{'} (x) cos (y) + 2 x sin (y) = - 2 x

Solve separable ODE:

y = arcsin (e^{- x^{2} + c_{1}} - 1) + 2 πn, y = π + arcsin (- e^{- x^{2} + c_{1}} + 1) + 2 πn

y = arcsin (e^{- x^{2} + c_{1}} - 1) + 2 πn, y = π + arcsin (- e^{- x^{2} + c_{1}} + 1) + 2 πn

y^{^{'}} = y^{2} + y - 30

x \frac{d y}{d x} + 4 y = 0

y^{^{'}} = x y^{3} (1 + x^{2})

\frac{d y}{y} = \frac{d x}{1 + x}

\frac{d y}{d x} y = e^{x^{2} l n (x)}