dy=(y+1)/(x+4)dx

解答

d y = \frac{y + 1}{x + 4} d x

y = e^{c_{1}} x + 4 e^{c_{1}} - 1

求解步骤

d y = \frac{y + 1}{x + 4} d x

求解可分离方程:

y = e^{c_{1}} x + 4 e^{c_{1}} - 1

y = e^{c_{1}} x + 4 e^{c_{1}} - 1

y^{^{'}} = (15 x^{2} + 4) (6 y + 5)

\frac{d P}{d t} = a P (t) - b P (t)^{2}

y - 2 y^{^{'}} + 10 y = 0

\frac{d v}{d t} = 10 - \frac{1}{100} v, v = 0, t = 0

\frac{d y}{d x} = \frac{x 4 - y ^{2}}{1 + x ^{2}}