y^'=8x(y^2+1)

Lösung

y^{^{'}} = 8 x (y^{2} + 1)

y = tan (4 x^{2} + c_{1})

Schritte zur Lösung

y^{'} (x) = 8 x (y^{2} + 1)

Solve separable ODE:

y = tan (4 x^{2} + c_{1})

y = tan (4 x^{2} + c_{1})

(3 t^{5} + 1) y \frac{d y}{d t} = 4 t^{4}

\frac{d x}{d t} = \frac{1 - x ^{2}}{x t}

y^{^{'}} = \frac{x}{e ^{y}}

y^{^{'}} = \frac{x sin ( x )}{y}, y (0) = - 1

4 x y^{2} + (x^{2} + 1) y^{^{'}} = 0