y^'+y=9

Lösung

y^{^{'}} + y = 9

y = - e^{- t - c_{1}} + 9

Schritte zur Lösung

y^{'} (t) + y = 9

Solve separable ODE:

y = - e^{- t - c_{1}} + 9

y = - e^{- t - c_{1}} + 9

\frac{d y}{d x} + y x^{2} = 0

\frac{d y}{d x} = \frac{x y}{x ^{2} - 3 x + 2}

\frac{d v}{d t} = 8 - 3 v

(y^{2} + 2 y - 3) d x + (4 x y + 4 x) d y = 0

\frac{d y}{d x} = - \frac{3}{5} x^{5} y^{7}