1+t^2(dy)/(dt)=1+y^2

Lösung

1 + t^{2} \frac{d y}{d t} = 1 + y^{2}

y = - \frac{t}{- 1 + c _{1} t}

Schritte zur Lösung

1 + t^{2} \frac{d y}{d t} = 1 + y^{2}

Solve separable ODE:

y = - \frac{t}{- 1 + c _{1} t}

y = - \frac{t}{- 1 + c _{1} t}

\frac{d x}{d t} = t x

y^{^{'}} = (1 - 13 x) y^{2}, y (0) = - \frac{1}{4}

y^{^{'}} + \frac{y}{6} = 5, y (- 1) = 0

100 y + 0.01 y^{^{'}} = 500

\frac{d y}{d x} y = 7 x^{3}