y^'=(1-y)^2

Lösung

y^{^{'}} = (1 - y)^{2}

y = - \frac{1}{t + c _{1}} + \frac{t}{t + c _{1}} + \frac{c _{1}}{t + c _{1}}

Schritte zur Lösung

y^{'} (t) = (1 - y)^{2}

Solve separable ODE:

y = - \frac{1}{t + c _{1}} + \frac{t}{t + c _{1}} + \frac{c _{1}}{t + c _{1}}

y = - \frac{1}{t + c _{1}} + \frac{t}{t + c _{1}} + \frac{c _{1}}{t + c _{1}}

\frac{d}{d x} ((y - 3)^{2}) = 2 - (x - 1)^{2}

\frac{d}{df} (H (f)) = 3 u (f)^{2} f

x^{^{'}} = 0.0175 - 0.3821 x

2 \frac{d x}{d t} + \frac{d x}{d t} - 2 x = 1

(2 + t) y^{^{'}} = 3 y