y^'=e^{2y}sin(x)

Lösung

y^{^{'}} = e^{2 y} sin (x)

y = - \frac{ln ( 2 cos ( x ) - c _{1} )}{2}

Schritte zur Lösung

y^{'} (x) = e^{2 y} sin (x)

Solve separable ODE:

y = - \frac{ln ( 2 cos ( x ) - c _{1} )}{2}

y = - \frac{ln ( 2 cos ( x ) - c _{1} )}{2}

\frac{d y}{d t} = t^{2} y + 1 + y + t^{2}

e^{x + y} y^{^{'}} = x, y (0) = ln (2)

y^{^{'}} = y + 5

(x ln (x^{2})) y^{^{'}} = 2 y

\frac{d y}{d t} + 0.5 t y = 4 t