-y^'-y=0

Lösung

- y^{^{'}} - y = 0

y = e^{- t - c_{1}}

Schritte zur Lösung

- y^{'} (t) - y = 0

Solve separable ODE:

y = e^{- t - c_{1}}

y = e^{- t - c_{1}}

\frac{d y}{d x} = \frac{y}{3 x - 1}

4 y y^{^{'}} = x, y (4) = 9

y^{^{'}} = y^{2} - 3 y + 2

\frac{d y}{d x} y = 6 u - 5, u = (\frac{1}{3}) x^{7}

y^{^{'}} = 1 + y^{2}, y (0) = 1